M^4-13m^2+42=0

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Solution for M^4-13m^2+42=0 equation: 



^4-13M^2+42=0

We add all the numbers together, and all the variables

-13M^2=0

a = -13; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-13)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$M=\frac{-b}{2a}=\frac{0}{-26}=0$

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